Optimal. Leaf size=180 \[ -\frac{b n \text{PolyLog}\left (2,-d f x^2\right )}{8 d^2 f^2}-\frac{\log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )+\frac{b n \log \left (d f x^2+1\right )}{16 d^2 f^2}-\frac{3 b n x^2}{16 d f}-\frac{1}{16} b n x^4 \log \left (d f x^2+1\right )+\frac{1}{16} b n x^4 \]
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Rubi [A] time = 0.165715, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {2454, 2395, 43, 2376, 2391} \[ -\frac{b n \text{PolyLog}\left (2,-d f x^2\right )}{8 d^2 f^2}-\frac{\log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \log \left (d f x^2+1\right ) \left (a+b \log \left (c x^n\right )\right )+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )+\frac{b n \log \left (d f x^2+1\right )}{16 d^2 f^2}-\frac{3 b n x^2}{16 d f}-\frac{1}{16} b n x^4 \log \left (d f x^2+1\right )+\frac{1}{16} b n x^4 \]
Antiderivative was successfully verified.
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Rule 2454
Rule 2395
Rule 43
Rule 2376
Rule 2391
Rubi steps
\begin{align*} \int x^3 \left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (\frac{1}{d}+f x^2\right )\right ) \, dx &=\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-(b n) \int \left (\frac{x}{4 d f}-\frac{x^3}{8}-\frac{\log \left (1+d f x^2\right )}{4 d^2 f^2 x}+\frac{1}{4} x^3 \log \left (1+d f x^2\right )\right ) \, dx\\ &=-\frac{b n x^2}{8 d f}+\frac{1}{32} b n x^4+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-\frac{1}{4} (b n) \int x^3 \log \left (1+d f x^2\right ) \, dx+\frac{(b n) \int \frac{\log \left (1+d f x^2\right )}{x} \, dx}{4 d^2 f^2}\\ &=-\frac{b n x^2}{8 d f}+\frac{1}{32} b n x^4+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-\frac{b n \text{Li}_2\left (-d f x^2\right )}{8 d^2 f^2}-\frac{1}{8} (b n) \operatorname{Subst}\left (\int x \log (1+d f x) \, dx,x,x^2\right )\\ &=-\frac{b n x^2}{8 d f}+\frac{1}{32} b n x^4+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )-\frac{1}{16} b n x^4 \log \left (1+d f x^2\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-\frac{b n \text{Li}_2\left (-d f x^2\right )}{8 d^2 f^2}+\frac{1}{16} (b d f n) \operatorname{Subst}\left (\int \frac{x^2}{1+d f x} \, dx,x,x^2\right )\\ &=-\frac{b n x^2}{8 d f}+\frac{1}{32} b n x^4+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )-\frac{1}{16} b n x^4 \log \left (1+d f x^2\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-\frac{b n \text{Li}_2\left (-d f x^2\right )}{8 d^2 f^2}+\frac{1}{16} (b d f n) \operatorname{Subst}\left (\int \left (-\frac{1}{d^2 f^2}+\frac{x}{d f}+\frac{1}{d^2 f^2 (1+d f x)}\right ) \, dx,x,x^2\right )\\ &=-\frac{3 b n x^2}{16 d f}+\frac{1}{16} b n x^4+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{4 d f}-\frac{1}{8} x^4 \left (a+b \log \left (c x^n\right )\right )+\frac{b n \log \left (1+d f x^2\right )}{16 d^2 f^2}-\frac{1}{16} b n x^4 \log \left (1+d f x^2\right )-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )}{4 d^2 f^2}+\frac{1}{4} x^4 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+d f x^2\right )-\frac{b n \text{Li}_2\left (-d f x^2\right )}{8 d^2 f^2}\\ \end{align*}
Mathematica [C] time = 0.100348, size = 348, normalized size = 1.93 \[ -\frac{1}{2} b d f n \left (\frac{\text{PolyLog}\left (2,-i \sqrt{d} \sqrt{f} x\right )+\log (x) \log \left (1+i \sqrt{d} \sqrt{f} x\right )}{2 d^3 f^3}+\frac{\text{PolyLog}\left (2,i \sqrt{d} \sqrt{f} x\right )+\log (x) \log \left (1-i \sqrt{d} \sqrt{f} x\right )}{2 d^3 f^3}-\frac{\frac{1}{2} x^2 \log (x)-\frac{x^2}{4}}{d^2 f^2}+\frac{\frac{1}{4} x^4 \log (x)-\frac{x^4}{16}}{d f}\right )-\frac{a \log \left (d f x^2+1\right )}{4 d^2 f^2}+\frac{a x^2}{4 d f}+\frac{1}{4} a x^4 \log \left (d f x^2+1\right )-\frac{a x^4}{8}+\frac{b \left (n-4 \left (\log \left (c x^n\right )-n \log (x)\right )\right ) \log \left (d f x^2+1\right )}{16 d^2 f^2}+\frac{1}{16} b x^4 \left (4 \left (\log \left (c x^n\right )-n \log (x)\right )+4 n \log (x)-n\right ) \log \left (d f x^2+1\right )+\frac{b x^2 \left (4 \left (\log \left (c x^n\right )-n \log (x)\right )-n\right )}{16 d f}+\frac{1}{32} b x^4 \left (n-4 \left (\log \left (c x^n\right )-n \log (x)\right )\right ) \]
Antiderivative was successfully verified.
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Maple [C] time = 0.095, size = 827, normalized size = 4.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{16} \,{\left (4 \, b x^{4} \log \left (x^{n}\right ) -{\left (b{\left (n - 4 \, \log \left (c\right )\right )} - 4 \, a\right )} x^{4}\right )} \log \left (d f x^{2} + 1\right ) - \int \frac{4 \, b d f x^{5} \log \left (x^{n}\right ) +{\left (4 \, a d f -{\left (d f n - 4 \, d f \log \left (c\right )\right )} b\right )} x^{5}}{8 \,{\left (d f x^{2} + 1\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (b x^{3} \log \left (d f x^{2} + 1\right ) \log \left (c x^{n}\right ) + a x^{3} \log \left (d f x^{2} + 1\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \log \left (c x^{n}\right ) + a\right )} x^{3} \log \left ({\left (f x^{2} + \frac{1}{d}\right )} d\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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